2g^2-9g-11=0

Solution for 2g^2-9g-11=0 equation:

2g^2-9g-11=0

a = 2; b = -9; c = -11;
Δ = b2-4ac
Δ = -92-4·2·(-11)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-13}{2*2}=\frac{-4}{4}
=-1
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+13}{2*2}=\frac{22}{4}
=5+1/2
$